The UNIVARIATE Procedure

Example 4.34 Comparing Weibull Quantile Plots

This example compares the use of three-parameter and two-parameter Weibull Q-Q plots for the failure times in months for 48 integrated circuits. The times are assumed to follow a Weibull distribution. The following statements save the failure times as the values of the variable Time in the data set Failures:

data Failures;
   input Time @@;
   label Time = 'Time in Months';
   datalines;
29.42 32.14 30.58 27.50 26.08 29.06 25.10 31.34
29.14 33.96 30.64 27.32 29.86 26.28 29.68 33.76
29.32 30.82 27.26 27.92 30.92 24.64 32.90 35.46
30.28 28.36 25.86 31.36 25.26 36.32 28.58 28.88
26.72 27.42 29.02 27.54 31.60 33.46 26.78 27.82
29.18 27.94 27.66 26.42 31.00 26.64 31.44 32.52
;

If no assumption is made about the parameters of this distribution, you can use the WEIBULL option to request a three-parameter Weibull plot. As in the previous example, you can visually estimate the shape parameter $c$ by requesting plots for different values of $c$ and choosing the value of $c$ that linearizes the point pattern. Alternatively, you can request a maximum likelihood estimate for $c$, as illustrated in the following statements:

symbol v=plus;
title 'Three-Parameter Weibull Q-Q Plot for Failure Times';
ods graphics off;
proc univariate data=Failures noprint;
   qqplot Time / weibull(c=est theta=est sigma=est)
                 square
                 href=0.5 1 1.5 2
                 vref=25 27.5 30 32.5 35
                 lhref=4 lvref=4;
run;

Note: When using the WEIBULL option, you must either specify a list of values for the Weibull shape parameter $c$ with the C= option or specify C=EST.

Output 4.34.1 displays the plot for the estimated value $\hat{c}=1.99$. The reference line corresponds to the estimated values for the threshold and scale parameters of $\hat{\theta }=24.19$ and $\hat{\sigma }_0=5.83$, respectively.

Output 4.34.1: Three-Parameter Weibull Q-Q Plot

Three-Parameter Weibull Q-Q Plot


Now, suppose it is known that the circuit lifetime is at least 24 months. The following statements use the known threshold value $\theta _0=24$ to produce the two-parameter Weibull Q-Q plot shown in Output 4.31.4:

symbol v=plus;
title 'Two-Parameter Weibull Q-Q Plot for Failure Times';
ods graphics off;
proc univariate data=Failures noprint;
   qqplot Time / weibull(theta=24 c=est sigma=est)
                 square
                 vref= 25 to 35 by 2.5
                 href= 0.5 to 2.0 by 0.5
                 lhref=4 lvref=4;
run;

The reference line is based on maximum likelihood estimates $\hat{c}=2.08$ and $\hat{\sigma }=6.05$.

Output 4.34.2: Two-Parameter Weibull Q-Q Plot for $\theta _0=24$

Two-Parameter Weibull Q-Q Plot for θ0=24


A sample program for this example, uniex19.sas, is available in the SAS Sample Library for Base SAS software.