Frequency Tables and Statistics |
The FREQ procedure provides easy access to statistics for testing for association in a crosstabulation table.
In this example, high school students applied for courses in a summer enrichment program; these courses included journalism, art history, statistics, graphic arts, and computer programming. The students accepted were randomly assigned to classes with and without internships in local companies. Table 36.1 contains counts of the students who enrolled in the summer program by gender and whether they were assigned an internship slot.
Enrollment |
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---|---|---|---|---|
Gender |
Internship |
Yes |
No |
Total |
boys |
yes |
35 |
29 |
64 |
boys |
no |
14 |
27 |
41 |
girls |
yes |
32 |
10 |
42 |
girls |
no |
53 |
23 |
76 |
The SAS data set SummerSchool is created by inputting the summer enrichment data as cell count data, or providing the frequency count for each combination of variable values. The following DATA step statements create the SAS data set SummerSchool:
data SummerSchool; input Gender $ Internship $ Enrollment $ Count @@; datalines; boys yes yes 35 boys yes no 29 boys no yes 14 boys no no 27 girls yes yes 32 girls yes no 10 girls no yes 53 girls no no 23 ;
The variable Gender takes the values ‘boys’ or ‘girls,’ the variable Internship takes the values ‘yes’ and ‘no,’ and the variable Enrollment takes the values ‘yes’ and ‘no.’ The variable Count contains the number of students that correspond to each combination of data values. The double at sign (@@) indicates that more than one observation is included on a single data line. In this DATA step, two observations are included on each line.
Researchers are interested in whether there is an association between internship status and summer program enrollment. The Pearson chi-square statistic is an appropriate statistic to assess the association in the corresponding table. The following PROC FREQ statements specify this analysis.
You specify the table for which you want to compute statistics with the TABLES statement. You specify the statistics you want to compute with options after a slash (/) in the TABLES statement.
proc freq data=SummerSchool order=data; tables Internship*Enrollment / chisq; weight Count; run;
The ORDER= option controls the order in which variable values are displayed in the rows and columns of the table. By default, the values are arranged according to the alphanumeric order of their unformatted values. If you specify ORDER=DATA, the data are displayed in the same order as they occur in the input data set. Here, because ‘yes’ appears before ‘no’ in the data, ‘yes’ appears first in any table. Other options for controlling order include ORDER=FORMATTED, which orders according to the formatted values, and ORDER=FREQUENCY, which orders by descending frequency count.
In the TABLES statement, Internship*Enrollment specifies a table where the rows are internship status and the columns are program enrollment. The CHISQ option requests chi-square statistics for assessing association between these two variables. Because the input data are in cell count form, the WEIGHT statement is required. The WEIGHT statement names the variable Count, which provides the frequency of each combination of data values.
Figure 36.1 presents the crosstabulation of Internship and Enrollment. In each cell, the values printed under the cell count are the table percentage, row percentage, and column percentage, respectively. For example, in the first cell, 63.21 percent of the students offered courses with internships accepted them and 36.79 percent did not.
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Figure 36.2 displays the statistics produced by the CHISQ option. The Pearson chi-square statistic is labeled 'Chi-Square' and has a value of 0.8189 with 1 degree of freedom. The associated -value is 0.3655, which means that there is no significant evidence of an association between internship status and program enrollment. The other chi-square statistics have similar values and are asymptotically equivalent. The other statistics (phi coefficient, contingency coefficient, and Cramer’s ) are measures of association derived from the Pearson chi-square. For Fisher’s exact test, the two-sided -value is 0.4122, which also shows no association between internship status and program enrollment.
Statistic | DF | Value | Prob |
---|---|---|---|
Chi-Square | 1 | 0.8189 | 0.3655 |
Likelihood Ratio Chi-Square | 1 | 0.8202 | 0.3651 |
Continuity Adj. Chi-Square | 1 | 0.5899 | 0.4425 |
Mantel-Haenszel Chi-Square | 1 | 0.8153 | 0.3666 |
Phi Coefficient | 0.0606 | ||
Contingency Coefficient | 0.0605 | ||
Cramer's V | 0.0606 |
Fisher's Exact Test | |
---|---|
Cell (1,1) Frequency (F) | 67 |
Left-sided Pr <= F | 0.8513 |
Right-sided Pr >= F | 0.2213 |
Table Probability (P) | 0.0726 |
Two-sided Pr <= P | 0.4122 |
The analysis, so far, has ignored gender. However, it might be of interest to ask whether program enrollment is associated with internship status after adjusting for gender. You can address this question by doing an analysis of a set of tables (in this case, by analyzing the set consisting of one for boys and one for girls). The Cochran-Mantel-Haenszel (CMH) statistic is appropriate for this situation: it addresses whether rows and columns are associated after controlling for the stratification variable. In this case, you would be stratifying by gender.
The PROC FREQ statements for this analysis are very similar to those for the first analysis, except that there is a third variable, Gender, in the TABLES statement. When you cross more than two variables, the two rightmost variables construct the rows and columns of the table, respectively, and the leftmost variables determine the stratification.
The following PROC FREQ statements also request frequency plots for the crosstabulation tables. PROC FREQ produces these plots by using ODS Graphics to create graphs as part of the procedure output. ODS Graphics must be enabled before producing plots.
ods graphics on; proc freq data=SummerSchool; tables Gender*Internship*Enrollment / chisq cmh plots(only)=freqplot; weight Count; run; ods graphics off;
This execution of PROC FREQ first produces two individual crosstabulation tables of Internship by Enrollment: one for boys and one for girls. Frequency plots and chi-square statistics are produced for each individual table. Figure 36.3, Figure 36.4, and Figure 36.5 show the results for boys. Note that the chi-square statistic for boys is significant at the level of significance. Boys offered a course with an internship are more likely to enroll than boys who are not.
Figure 36.4 displays the frequency plot of Internship by Enrollment for boys. By default, the frequency plot is displayed as a bar chart with vertical grouping by the row variable Internship. You can use PLOTS= options to request a dot plot instead of a bar chart or to change the orientation of the bars from vertical to horizontal. You can also use PLOTS= options to specify other two-way layouts such as stacked or horizontal grouping.
Figure 36.6, Figure 36.7, and Figure 36.8 display the crosstabulation table, frequency plot, and chi-square statistics for girls. You can see that there is no evidence of association between internship offers and program enrollment for girls.
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Statistic | DF | Value | Prob |
---|---|---|---|
Chi-Square | 1 | 4.2366 | 0.0396 |
Likelihood Ratio Chi-Square | 1 | 4.2903 | 0.0383 |
Continuity Adj. Chi-Square | 1 | 3.4515 | 0.0632 |
Mantel-Haenszel Chi-Square | 1 | 4.1963 | 0.0405 |
Phi Coefficient | 0.2009 | ||
Contingency Coefficient | 0.1969 | ||
Cramer's V | 0.2009 |
Fisher's Exact Test | |
---|---|
Cell (1,1) Frequency (F) | 27 |
Left-sided Pr <= F | 0.9885 |
Right-sided Pr >= F | 0.0311 |
Table Probability (P) | 0.0196 |
Two-sided Pr <= P | 0.0467 |
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Statistic | DF | Value | Prob |
---|---|---|---|
Chi-Square | 1 | 0.5593 | 0.4546 |
Likelihood Ratio Chi-Square | 1 | 0.5681 | 0.4510 |
Continuity Adj. Chi-Square | 1 | 0.2848 | 0.5936 |
Mantel-Haenszel Chi-Square | 1 | 0.5545 | 0.4565 |
Phi Coefficient | 0.0688 | ||
Contingency Coefficient | 0.0687 | ||
Cramer's V | 0.0688 |
Fisher's Exact Test | |
---|---|
Cell (1,1) Frequency (F) | 23 |
Left-sided Pr <= F | 0.8317 |
Right-sided Pr >= F | 0.2994 |
Table Probability (P) | 0.1311 |
Two-sided Pr <= P | 0.5245 |
These individual table results demonstrate the occasional problems with combining information into one table and not accounting for information in other variables such as Gender. Figure 36.9 contains the CMH results. There are three summary (CMH) statistics; which one you use depends on whether your rows and/or columns have an order in tables. However, in the case of tables, ordering does not matter and all three statistics take the same value. The CMH statistic follows the chi-square distribution under the hypothesis of no association, and here, it takes the value 4.0186 with 1 degree of freedom. The associated -value is 0.0450, which indicates a significant association at the level.
Thus, when you adjust for the effect of gender in these data, there is an association between internship and program enrollment. But, if you ignore gender, no association is found. Note that the CMH option also produces other statistics, including estimates and confidence limits for relative risk and odds ratios for tables and the Breslow-Day Test. These results are not displayed here.
Cochran-Mantel-Haenszel Statistics (Based on Table Scores) | ||||
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Statistic | Alternative Hypothesis | DF | Value | Prob |
1 | Nonzero Correlation | 1 | 4.0186 | 0.0450 |
2 | Row Mean Scores Differ | 1 | 4.0186 | 0.0450 |
3 | General Association | 1 | 4.0186 | 0.0450 |