The FREQ Procedure

Frequency Tables and Statistics

The FREQ procedure provides easy access to statistics for testing for association in a crosstabulation table.

In this example, high school students applied for courses in a summer enrichment program; these courses included journalism, art history, statistics, graphic arts, and computer programming. The students accepted were randomly assigned to classes with and without internships in local companies. Table 3.1 contains counts of the students who enrolled in the summer program by gender and whether they were assigned an internship slot.

Table 3.1: Summer Enrichment Data

   

Enrollment

Gender

Internship

Yes

No

Total

boys

yes

35

29

64

boys

no

14

27

41

girls

yes

32

10

42

girls

no

53

23

76


The SAS data set SummerSchool is created by inputting the summer enrichment data as cell count data, or providing the frequency count for each combination of variable values. The following DATA step statements create the SAS data set SummerSchool:

data SummerSchool; 
   input Gender $ Internship $ Enrollment $ Count @@; 
   datalines;
boys  yes yes 35   boys  yes no 29 
boys   no yes 14   boys   no no 27
girls yes yes 32   girls yes no 10  
girls  no yes 53   girls  no no 23
;

The variable Gender takes the values ‘boys’ or ‘girls,’ the variable Internship takes the values ‘yes’ and ‘no,’ and the variable Enrollment takes the values ‘yes’ and ‘no.’ The variable Count contains the number of students that correspond to each combination of data values. The double at sign (@@) indicates that more than one observation is included on a single data line. In this DATA step, two observations are included on each line.

Researchers are interested in whether there is an association between internship status and summer program enrollment. The Pearson chi-square statistic is an appropriate statistic to assess the association in the corresponding $2 \times 2$ table. The following PROC FREQ statements specify this analysis.

You specify the table for which you want to compute statistics with the TABLES statement. You specify the statistics you want to compute with options after a slash (/) in the TABLES statement.

proc freq data=SummerSchool order=data;
   tables Internship*Enrollment / chisq;
   weight Count;
run;

The ORDER= option controls the order in which variable values are displayed in the rows and columns of the table. By default, the values are arranged according to the alphanumeric order of their unformatted values. If you specify ORDER=DATA, the data are displayed in the same order as they occur in the input data set. Here, because ‘yes’ appears before ‘no’ in the data, ‘yes’ appears first in any table. Other options for controlling order include ORDER=FORMATTED, which orders according to the formatted values, and ORDER=FREQUENCY, which orders by descending frequency count.

In the TABLES statement, Internship*Enrollment specifies a table where the rows are internship status and the columns are program enrollment. The CHISQ option requests chi-square statistics for assessing association between these two variables. Because the input data are in cell count form, the WEIGHT statement is required. The WEIGHT statement names the variable Count, which provides the frequency of each combination of data values.

Figure 3.1 presents the crosstabulation of Internship and Enrollment. In each cell, the values printed under the cell count are the table percentage, row percentage, and column percentage, respectively. For example, in the first cell, 63.21 percent of the students offered courses with internships accepted them and 36.79 percent did not.

Figure 3.1: Crosstabulation Table

The FREQ Procedure

Frequency
Percent
Row Pct
Col Pct
Table of Internship by Enrollment
Internship Enrollment
yes no Total
yes
67
30.04
63.21
50.00
39
17.49
36.79
43.82
106
47.53
 
 
no
67
30.04
57.26
50.00
50
22.42
42.74
56.18
117
52.47
 
 
Total
134
60.09
89
39.91
223
100.00



Figure 3.2 displays the statistics produced by the CHISQ option. The Pearson chi-square statistic is labeled 'Chi-Square' and has a value of 0.8189 with 1 degree of freedom. The associated p-value is 0.3655, which means that there is no significant evidence of an association between internship status and program enrollment. The other chi-square statistics have similar values and are asymptotically equivalent. The other statistics (phi coefficient, contingency coefficient, and Cramér’s V) are measures of association derived from the Pearson chi-square. For Fisher’s exact test, the two-sided p-value is 0.4122, which also shows no association between internship status and program enrollment.

Figure 3.2: Statistics Produced with the CHISQ Option

Statistic DF Value Prob
Chi-Square 1 0.8189 0.3655
Likelihood Ratio Chi-Square 1 0.8202 0.3651
Continuity Adj. Chi-Square 1 0.5899 0.4425
Mantel-Haenszel Chi-Square 1 0.8153 0.3666
Phi Coefficient   0.0606  
Contingency Coefficient   0.0605  
Cramer's V   0.0606  

Fisher's Exact Test
Cell (1,1) Frequency (F) 67
Left-sided Pr <= F 0.8513
Right-sided Pr >= F 0.2213
   
Table Probability (P) 0.0726
Two-sided Pr <= P 0.4122



The analysis, so far, has ignored gender. However, it might be of interest to ask whether program enrollment is associated with internship status after adjusting for gender. You can address this question by doing an analysis of a set of tables (in this case, by analyzing the set consisting of one for boys and one for girls). The Cochran-Mantel-Haenszel (CMH) statistic is appropriate for this situation: it addresses whether rows and columns are associated after controlling for the stratification variable. In this case, you would be stratifying by gender.

The PROC FREQ statements for this analysis are very similar to those for the first analysis, except that there is a third variable, Gender, in the TABLES statement. When you cross more than two variables, the two rightmost variables construct the rows and columns of the table, respectively, and the leftmost variables determine the stratification.

The following PROC FREQ statements also request frequency plots for the crosstabulation tables. PROC FREQ produces these plots by using ODS Graphics to create graphs as part of the procedure output. ODS Graphics must be enabled before producing plots. The PLOTS(ONLY)=FREQPLOT option requests frequency plots. The TWOWAY=CLUSTER plot-option specifies a cluster layout for the two-way frequency plots.

ods graphics on;
proc freq data=SummerSchool;
   tables Gender*Internship*Enrollment /
          chisq cmh plots(only)=freqplot(twoway=cluster);
   weight Count;
run;
ods graphics off;

This execution of PROC FREQ first produces two individual crosstabulation tables of Internship by Enrollment: one for boys and one for girls. Frequency plots and chi-square statistics are produced for each individual table. Figure 3.3, Figure 3.4, and Figure 3.5 show the results for boys. Note that the chi-square statistic for boys is significant at the $\alpha =0.05$ level of significance. Boys offered a course with an internship are more likely to enroll than boys who are not.

Figure 3.4 displays the frequency plot of Internship by Enrollment for boys. By default, frequency plots are displayed as bar charts. You can use PLOTS= options to request dot plots instead of bar charts, to change the orientation of the bars from vertical to horizontal, and to change the scale from frequencies to percents. You can also use PLOTS= options to specify other two-way layouts (stacked, vertical groups, or horizontal groups) and to change the primary grouping from column levels to row levels.

Figure 3.6, Figure 3.7, and Figure 3.8 display the crosstabulation table, frequency plot, and chi-square statistics for girls. You can see that there is no evidence of association between internship offers and program enrollment for girls.

Figure 3.3: Crosstabulation Table for Boys

The FREQ Procedure

Frequency
Percent
Row Pct
Col Pct
Table 1 of Internship by Enrollment
Controlling for Gender=boys
Internship Enrollment
no yes Total
no
27
25.71
65.85
48.21
14
13.33
34.15
28.57
41
39.05
 
 
yes
29
27.62
45.31
51.79
35
33.33
54.69
71.43
64
60.95
 
 
Total
56
53.33
49
46.67
105
100.00



Figure 3.4: Frequency Plot for Boys

Frequency Plot for Boys


Figure 3.5: Chi-Square Statistics for Boys

Statistic DF Value Prob
Chi-Square 1 4.2366 0.0396
Likelihood Ratio Chi-Square 1 4.2903 0.0383
Continuity Adj. Chi-Square 1 3.4515 0.0632
Mantel-Haenszel Chi-Square 1 4.1963 0.0405
Phi Coefficient   0.2009  
Contingency Coefficient   0.1969  
Cramer's V   0.2009  

Fisher's Exact Test
Cell (1,1) Frequency (F) 27
Left-sided Pr <= F 0.9885
Right-sided Pr >= F 0.0311
   
Table Probability (P) 0.0196
Two-sided Pr <= P 0.0467



Figure 3.6: Crosstabulation Table for Girls

Frequency
Percent
Row Pct
Col Pct
Table 2 of Internship by Enrollment
Controlling for Gender=girls
Internship Enrollment
no yes Total
no
23
19.49
30.26
69.70
53
44.92
69.74
62.35
76
64.41
 
 
yes
10
8.47
23.81
30.30
32
27.12
76.19
37.65
42
35.59
 
 
Total
33
27.97
85
72.03
118
100.00



Figure 3.7: Frequency Plot for Girls

Frequency Plot for Girls


Figure 3.8: Chi-Square Statistics for Girls

Statistic DF Value Prob
Chi-Square 1 0.5593 0.4546
Likelihood Ratio Chi-Square 1 0.5681 0.4510
Continuity Adj. Chi-Square 1 0.2848 0.5936
Mantel-Haenszel Chi-Square 1 0.5545 0.4565
Phi Coefficient   0.0688  
Contingency Coefficient   0.0687  
Cramer's V   0.0688  

Fisher's Exact Test
Cell (1,1) Frequency (F) 23
Left-sided Pr <= F 0.8317
Right-sided Pr >= F 0.2994
   
Table Probability (P) 0.1311
Two-sided Pr <= P 0.5245



These individual table results demonstrate the occasional problems with combining information into one table and not accounting for information in other variables such as Gender. Figure 3.9 contains the CMH results. There are three summary (CMH) statistics; which one you use depends on whether your rows and/or columns have an order in $r \times c$ tables. However, in the case of $2 \times 2$ tables, ordering does not matter and all three statistics take the same value. The CMH statistic follows the chi-square distribution under the hypothesis of no association, and here, it takes the value 4.0186 with 1 degree of freedom. The associated p-value is 0.0450, which indicates a significant association at the $\alpha =0.05$ level.

Thus, when you adjust for the effect of gender in these data, there is an association between internship and program enrollment. But, if you ignore gender, no association is found. Note that the CMH option also produces other statistics, including estimates and confidence limits for relative risk and odds ratios for $2 \times 2$ tables and the Breslow-Day Test. These results are not displayed here.

Figure 3.9: Test for the Hypothesis of No Association

Cochran-Mantel-Haenszel Statistics (Based on Table Scores)
Statistic Alternative Hypothesis DF Value Prob
1 Nonzero Correlation 1 4.0186 0.0450
2 Row Mean Scores Differ 1 4.0186 0.0450
3 General Association 1 4.0186 0.0450