Example 65.2 A Hierarchical Design
     
In this example, three plants are nested within four pots, which are nested within three houses. The FACTORS statement requests a random permutation of the numbers 1, 2, and 3 to choose Houses randomly. The second step requests a random permutation of the numbers 1, 2, 3, and 4 for each of those first three numbers to randomly assign Pots to Houses. Finally, the FACTORS statement requests a random permutation of 1, 2, and 3 for each of the 12 integers in the second set of permutations. This last step randomly assigns Plants to Pots. The following statements produce Output  65.2.1: 
   title 'Hierarchical Design';
   proc plan seed=17431;
      factors Houses=3 Pots=4 Plants=3 / noprint;
      output out=nested;
   run;
   
   proc print data=nested;
   run;
    Output 65.2.1
    A Hierarchical Design
| 1 | 3 | 2 | 
| 1 | 3 | 3 | 
| 1 | 3 | 1 | 
| 1 | 1 | 3 | 
| 1 | 1 | 1 | 
| 1 | 1 | 2 | 
| 1 | 2 | 2 | 
| 1 | 2 | 3 | 
| 1 | 2 | 1 | 
| 1 | 4 | 3 | 
| 1 | 4 | 2 | 
| 1 | 4 | 1 | 
| 2 | 4 | 1 | 
| 2 | 4 | 3 | 
| 2 | 4 | 2 | 
| 2 | 2 | 2 | 
| 2 | 2 | 1 | 
| 2 | 2 | 3 | 
| 2 | 3 | 2 | 
| 2 | 3 | 3 | 
| 2 | 3 | 1 | 
| 2 | 1 | 2 | 
| 2 | 1 | 3 | 
| 2 | 1 | 1 | 
| 3 | 4 | 1 | 
| 3 | 4 | 3 | 
| 3 | 4 | 2 | 
| 3 | 1 | 3 | 
| 3 | 1 | 2 | 
| 3 | 1 | 1 | 
| 3 | 2 | 1 | 
| 3 | 2 | 2 | 
| 3 | 2 | 3 | 
| 3 | 3 | 3 | 
| 3 | 3 | 2 | 
| 3 | 3 | 1 |