DEPTAB Function

Returns the depreciation from specified tables.

Category:

Financial

Syntax

DEPTAB(p,v,t1,...,tn)

Required Arguments

p

is numeric, the period for which the calculation is to be done. For noninteger p arguments, the depreciation is prorated between the two consecutive time periods that precede and follow the fractional period.

v

is numeric, the depreciable initial value of the asset.

t1,t2, . . . ,tn

are numeric, the fractions of depreciation for each time period with t1+t2+...tn $\leq$ 1.

Details

The DEPTAB function returns the depreciation by using specified tables. The formula is

\begin{matrix} D E P T A B (p, v, t_{1}, t_{2}, . . ., t_{n}) & = D A C C T A B (p, v, t_{1}, t_{2}, . . ., t_{n}) \\ - D A C C T A B (p - 1, v, t_{1}, t_{2}, . . ., t_{n}) \end{matrix}

For a given p, only the arguments

t_{1}, t_{2}, \dots, t_{k}

need to be specified with k=ceil(p).

Example

An asset has a depreciable initial value of $1,000 and a five-year lifetime. Using a table of the annual depreciation rates of .15, .22, .21, .21, and .21 during the first, second, third, fourth, and fifth years, respectively, the depreciation in the third year can be expressed as

y3=deptab(3,1000,.15,.22,.21,.21,.21);

The value that is returned is 210.00. The fourth rate, .21, and the fifth rate, .21, can be omitted because they are not needed in the calculation.