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Explanation |
Explanation |
An explicit specialization declaration was found for a function that was not an instance of a function template or member of an unspecialized class generated from a template, or a function or class template that was not a member of an unspecialized class generated from a template. Note that the explicit specialization syntax is not used for members of explicitly specialized classes. See the C++ standard, section 14.7.3, paragraphs 1 and 5.
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