Syntax Examples (omods01)
/***************************************************************/
/* */
/* S A S S A M P L E L I B R A R Y */
/* */
/* NAME: omods01 */
/* TITLE: Syntax Examples (omods01) */
/* PRODUCT: OR */
/* SYSTEM: ALL */
/* KEYS: OR */
/* PROCS: OPTMODEL */
/* DATA: */
/* */
/* SUPPORT: UPDATE: */
/* REF: */
/* MISC: Examples from the Syntax section of the */
/* OPTMODEL chapter of Mathematical Programming. */
/* */
/***************************************************************/
/****************************************************************
* *
* Declaration Statements *
* *
****************************************************************/
/* NUMBER, STRING, and SET Parameters */
proc optmodel;
num a{i in 1..2} init i**2;
a[1] = 2;
put a[*]=;
quit;
/* NUMBER, STRING, and SET Parameters: Initializing Arrays */
proc optmodel;
number a{1..3} = [5 4 7];
number b{1..3} INIT [5 4 7];
put a[*]=;
b[1] = 1;
put b[*]=;
quit;
/****************************************************************
* *
* Programming Statements *
* *
****************************************************************/
/* COFOR Statement: A Simple Loop */
proc optmodel printlevel=0;
var x {1..6} >= 0;
minimize z = sum {j in 1..6} x[j];
con a1: x[1] + x[2] + x[3] <= 4;
con a2: x[4] + x[5] + x[6] <= 6;
con a3: x[1] + x[4] >= 5;
con a4: x[2] + x[5] >= 2;
con a5: x[3] + x[6] >= 3;
cofor{i in 3..5} do;
fix x[1]=i;
solve;
put i= x[1]= _solution_status_=;
end;
quit;
/* Monte Carlo MINLP Portfolio Optimization */
/* Expected Return For Assets */
data means;
input return;
datalines;
0.000065763
0.002604107
0.000753611
0.000082178
-.000380250
0.000399003
0.002421262
0.002412429
0.000773394
0.000403047
0.001361435
;
/* Asset Return Covariance */
data covdata;
input cov asset1 asset2;
datalines;
0.001353751 1 1
0.000468578 1 2
0.001280990 1 3
-.000032003 1 4
0.000731890 1 5
0.000660113 1 6
0.000641176 1 7
0.000466734 1 8
0.000683927 1 9
0.000658789 1 10
0.000606616 1 11
0.000307035 2 2
0.000534959 2 3
-.000006434 2 4
0.000310362 2 5
0.000304408 2 6
0.000348148 2 7
0.000243561 2 8
0.000311989 2 9
0.000301229 2 10
0.000282500 2 11
0.001448759 3 3
-.000031943 3 4
0.000772008 3 5
0.000745441 3 6
0.000782744 3 7
0.000554453 3 8
0.000762838 3 9
0.000745559 3 10
0.000719599 3 11
0.000026314 4 4
-.000027629 4 5
-.000025069 4 6
-.000016775 4 7
-.000016202 4 8
-.000026060 4 9
-.000026031 4 10
-.000019917 4 11
0.000510235 5 5
0.000463580 5 6
0.000471570 5 7
0.000346507 5 8
0.000479810 5 9
0.000463526 5 10
0.000424889 5 11
0.000455959 6 6
0.000471924 6 7
0.000332697 6 8
0.000462159 6 9
0.000455080 6 10
0.000421059 6 11
0.000572171 7 7
0.000371153 7 8
0.000473532 7 9
0.000470686 7 10
0.000449428 7 11
0.000316483 8 8
0.000337295 8 9
0.000331312 8 10
0.000328404 8 11
0.000482038 9 9
0.000462024 9 10
0.000429875 9 11
0.000456097 10 10
0.000420613 10 11
0.000460050 11 11
;
/* COFOR Statement: Optimization With a Fixed Number Of Trials */
proc optmodel printlevel=0;
/* assets and related parameters */
set ASSETS;
num return {ASSETS};
num cov {ASSETS, ASSETS} init 0;
read data means into ASSETS=[_n_] return;
read data covdata into [asset1 asset2] cov cov[asset2,asset1]=cov;
num riskLimit init 0.00025;
num minThreshold init 0.1;
num numTrials = 10;
/* number of random trials */
set TRIALS = 1..numTrials;
/* declare NLP problem for fixed set of assets */
set ASSETS_THIS;
var AssetPropVar {ASSETS} >= minThreshold <= 1;
max ExpectedReturn = sum {i in ASSETS} return[i] * AssetPropVar[i];
con RiskBound:
sum {i in ASSETS_THIS, j in ASSETS_THIS}
cov[i,j] * AssetPropVar[i] * AssetPropVar[j] <= riskLimit;
con TotalPortfolio:
sum {asset in ASSETS} AssetPropVar[asset] = 1;
/* parameters to track best solution */
num infinity = constant('BIG');
num best_objective init -infinity;
set INCUMBENT;
/* iterate over trials */
num start {TRIALS};
num finish {TRIALS};
num overall_start;
overall_start = time();
call streaminit(1);
cofor {trial in TRIALS} do;
start[trial] = time() - overall_start;
put;
put trial=;
ASSETS_THIS = {i in ASSETS: rand('UNIFORM') < 0.5};
put ASSETS_THIS=;
for {i in ASSETS diff ASSETS_THIS}
fix AssetPropVar[i] = 0;
solve with NLP / logfreq=0;
put _solution_status_=;
if _solution_status_ ne 'INFEASIBLE' then do;
if best_objective < ExpectedReturn then do;
best_objective = ExpectedReturn;
INCUMBENT = ASSETS_THIS;
end;
end;
finish[trial] = time() - overall_start;
end;
put best_objective= INCUMBENT=;
create data ganttdata from [trial] e_start=start e_finish=finish;
quit;
proc gantt data=ganttdata;
id trial;
chart / compress nolegend nojobnum mindate=0 top height=1.8;
run;
/* COFOR Statement: Optimization With a Time Limit Using LEAVE */
proc optmodel printlevel=0;
set ASSETS;
num return {ASSETS};
num cov {ASSETS, ASSETS} init 0;
read data means into ASSETS=[_n_] return;
read data covdata into [asset1 asset2] cov cov[asset2,asset1]=cov;
num riskLimit init 0.00025;
num minThreshold init 0.1;
/* declare NLP problem for fixed set of assets */
set ASSETS_THIS;
var AssetPropVar {ASSETS} >= minThreshold <= 1;
max ExpectedReturn = sum {i in ASSETS} return[i] * AssetPropVar[i];
con RiskBound:
sum {i in ASSETS_THIS, j in ASSETS_THIS}
cov[i,j] * AssetPropVar[i] * AssetPropVar[j] <= riskLimit;
con TotalPortfolio:
sum {asset in ASSETS} AssetPropVar[asset] = 1;
num infinity = constant('BIG');
num best_objective init -infinity;
set INCUMBENT;
/* run for 30 seconds */
num last_time;
last_time = time() + 30;
num n_trials init 0;
call streaminit(1);
cofor {trial in 1..1e9} do;
put;
put trial=;
ASSETS_THIS = {i in ASSETS: rand('UNIFORM') < 0.5};
put ASSETS_THIS=;
for {i in ASSETS diff ASSETS_THIS} fix AssetPropVar[i] = 0;
solve with NLP / logfreq=0;
put _solution_status_=;
if _solution_status_ ne 'INFEASIBLE' then do;
if best_objective < ExpectedReturn then do;
best_objective = ExpectedReturn;
INCUMBENT = ASSETS_THIS;
end;
end;
n_trials = n_trials + 1;
if time() >= last_time then leave;
end;
put n_trials=;
put best_objective= INCUMBENT=;
quit;
/* CREATE DATA Statement: Columns */
proc optmodel;
set<string> alph = {'a', 'b', 'c'};
var x{1..3, alph} init 2;
create data example from [i]=(1..3)
{j in alph}<col("x"||j)=x[i,j]>;
quit;
/* CREATE DATA Statement: Creating a Single Observation */
proc optmodel;
number m = 7, n = 5;
create data example from m n ratio=(m/n) col("s"||n)=(m+n);
quit;
proc print;
run;
/* CREATE DATA Statement: Column Options */
proc optmodel;
num sq{i in 1..10} = i*i;
create data squares from [i/format=hex2./length=3] sq/format=6.2;
quit;
proc print;
run;
/* CREATE DATA Statement: Key Columns */
proc optmodel;
number m{1..5, 1..3} = [[1 1] 1 [4 1] 1];
create data example
from [i j] = {setof{i in 1..2}<i**2>, {1, 2}} m;
quit;
proc print data=example noobs;
run;
/* CREATE DATA Statement: Unspecified Key-Set */
proc optmodel;
number x{1..2} init 2;
var y{2..3} init 3;
create data exdata from [keycol] x y;
quit;
proc print;
run;
/* CREATE DATA Statement: Iterated Columns */
proc optmodel;
num m = 3; /* number of rows/observations */
num n = 4; /* number of columns in a */
num a{i in 1..m, j in 1..n} = i*j; /* compute a */
num b{i in 1..m} = i**2; /* compute b */
set<num> subset = 2..m; /* used to omit first row */
create data out
from [i]=subset {j in 1..n}<col("a"||j)=a[i,j]> b;
quit;
/* DO Statement: DO Statement, Iterative */
proc optmodel;
number i;
do i=1,3,5;
put i;
end;
quit;
/* DO Statement: Iterating Over a Range */
proc optmodel;
number i;
do i=1 to 5 by 2;
put 'value of i assigned by the DO loop = ' i;
i=i**2;
put 'value of i assigned in the body of the loop = ' i;
end;
quit;
/* DO Statement: Iterating Over a Set */
proc optmodel;
set s = {1,3,5};
number i;
do i = s;
put i;
end;
quit;
/* DO Statement: Iterating With a WHILE Clause */
proc optmodel;
set s = {1,2,3,4,5};
number i;
do i = s while(i NE 4);
put i;
end;
quit;
/* DO UNTIL Statement */
proc optmodel;
number i;
i = 1;
do until (i=3);
put i;
i=i+1;
end;
quit;
/* DO WHILE Statement */
proc optmodel;
number i;
i = 1;
do while (i<3);
put i;
i=i+1;
end;
quit;
/* DROP Statement */
proc optmodel;
var x{1..10};
con c1: x[1] + x[2] <= 3;
con disp{i in 1..9}: x[i+1] >= x[i] + 0.1;
drop c1; /* drops the c1 constraint */
drop disp[5]; /* drops just disp[5] */
drop disp; /* drops all disp constraints */
quit;
/* EXPAND Statement */
proc optmodel;
number n=2;
var x{1..n};
min z1=sum{i in 1..n}(x[i]-i)**2;
max z2=sum{i in 1..n}(i-x[i])**3;
con c{i in 1..n}: x[i]>=0;
fix x[2]=3;
expand;
quit;
/* EXPAND Statement: SOLVE Option */
proc optmodel;
number n=2;
var x{1..n};
min z1=sum{i in 1..n}(x[i]-i)**2;
max z2=sum{i in 1..n}(i-x[i])**3;
con c{i in 1..n}: x[i]>=0;
fix x[2]=3;
expand / solve;
quit;
/* FOR Statement */
proc optmodel;
for {i in 1..2, j in {'a', 'b'}} put i= j=;
quit;
/* LEAVE Statement */
proc optmodel;
number i, j;
do i = 1..5;
do j = 1..4;
if i >= 3 and j = 2 then leave;
end;
print i j;
end;
quit;
/* PRINT Statement */
proc optmodel;
num x = 4.3;
var y{j in 1..4} init j*3.68;
print y; /* identifier-expression */
print (x * .265) dollar6.2; /* (expression) [format] */
print {i in 2..4} y; /* {index-set} identifier-expression */
print {i in 1..3}(i + i*.2345692) best7.;
/* {index-set} (expression) [format] */
print "Line 1"; /* string */
quit;
proc optmodel;
num a{i in 1..3} = i*i;
num b{i in 3..5} = 4*i;
print a b;
quit;
/* PRINT Statement: Matrix Output */
proc optmodel;
print {i in 1..6, j in i..6} (i*10+j);
quit;
/* PRINT Statement: PMATRIX= Option */
proc optmodel;
num a{i in 1..6, i..i} = i;
num b{i in 1..3, j in 1..3} = i*j;
print a;
print b;
reset options pmatrix=3;
print a;
reset options pmatrix=0.5;
print b;
quit;
/* READ DATA Statement: Key Columns */
data invdata;
input item $ invcount;
datalines;
table 100
sofa 250
chair 80
;
proc optmodel;
set<string> Items;
number invcount{Items};
read data invdata into Items=[item] invcount;
print invcount;
quit;
/* READ DATA Statement: Columns */
data exdata;
input column1 column2;
datalines;
1 2
3 4
;
proc optmodel;
number n init 2;
set<num> indx;
number p{indx}, q{indx};
read data exdata into
indx=[_N_] p=column1 q=col("column"||n);
print p q;
/* READ DATA Statement: Iterated Columns */
data dmnd;
input loc $ day1 day2 day3 day4 day5;
datalines;
East 1.1 2.3 1.3 3.6 4.7
West 7.0 2.1 6.1 5.8 3.2
;
proc optmodel;
set DOW = 1..5; /* days of week, 1=Monday, 5=Friday */
set<string> LOCS; /* locations */
number demand{LOCS, DOW};
read data dmnd
into LOCS=[loc]
{d in DOW} < demand[loc, d]=col("day"||d) >;
print demand;
quit;
/* SAVE MPS Statement */
proc optmodel;
var x >= 0, y >= 0;
con c: x >= y;
con bx: x <= 2;
con by: y <= 1;
min obj=0.5*x-y;
save mps MPSData;
quit;
proc optlp data=MPSData pout=PrimalOut dout=DualOut;
run;
/* SAVE QPS Statement */
proc optmodel;
var x{1..2} >= 0;
min z = 2*x[1] + 3 * x[2] + x[1]**2 + 10*x[2]**2
+ 2.5*x[1]*x[2];
con c1: x[1] - x[2] <= 1;
con c2: x[1] + 2*x[2] >= 100;
save qps QPSData;
quit;
proc optqp data=QPSData pout=PrimalOut dout=DualOut;
run;
/* STOP Statement */
proc optmodel;
number i, j;
do i = 1..5;
do j = 1..4;
if i = 3 and j = 2 then stop;
end;
end;
print i j;
quit;
/* SUBMIT Statement */
proc optmodel;
set<str> NODES;
num priority{NODES};
/* set up priority data... */
call streaminit(12345);
NODES = setof{i in 1..26} substr('ABCDEFGHIJKLMNOPQRSTUVWXYZ',i,1);
for {id in NODES} priority[id] = 100*rand('UNIFORM');
/* sort nodes by descending priority */
create data temppri from [id] priority;
submit;
proc sort;
by descending priority;
run;
endsubmit;
/* load nodes by priority */
str nodesByPri{i in 1..card(NODES)};
read data temppri into [_n_] nodesByPri=id;
/* use the sorted list... */
print nodesByPri {i in 1..card(NODES)} priority[nodesByPri[i]];
quit;
/* SUBMIT Statement Error Handling */
proc optmodel;
num success, syscc;
submit / OK = success out syscc;
data example;
set notfound;
j = i*i;
run;
endsubmit;
print success syscc;
quit;