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 The POWER Procedure

## Example 68.5 Multiple Regression and Correlation

You are working with a team of preventive cardiologists investigating whether elevated serum homocysteine levels are linked to atherosclerosis (plaque buildup) in coronary arteries. The planned analysis is an ordinary least squares regression to assess the relationship between total homocysteine level (tHcy) and a plaque burden index (PBI), adjusting for six other variables: age, gender, plasma levels of folate, vitamin , vitamin , and a serum cholesterol index. You will regress PBI on tHcy and the six other predictors (plus the intercept) and use a Type III test to assess whether tHcy is a significant predictor after adjusting for the others. You wonder whether 100 subjects will provide adequate statistical power.

This is a correlational study at a single time. Subjects will be screened so that about half will have had a heart problem. All eight variables will be measured during one visit. Most clinicians are familiar with simple correlations between two variables, so you decide to pose the statistical problem in terms of estimating and testing the partial correlation between = tHcy and = PBI, controlling for the six other predictor variables ( ). This greatly simplifies matters, especially the elicitation of the conjectured effect.

You use partial regression plots like that shown in Figure 68.9 to teach the team that the partial correlation between PBI and tHcy is the correlation of two sets of residuals obtained from ordinary regression models, one from regressing PBI on the six covariates and the other from regressing tHcy on the same covariates. Thus each subject has "expected" tHcy and PBI values based on the six covariates. The cardiologists believe that subjects whose tHcy is relatively higher than expected will also have a PBI that is relatively higher than expected. The partial correlation quantifies that adjusted association just as a standard simple correlation does with the unadjusted linear association between two variables.

Figure 68.9 Partial Regression Plot Based on previously published studies of various coronary risk factors and after viewing a set of scatterplots showing various correlations, the team surmises that the true partial correlation is likely to be at least 0.35.

You want to compute the statistical power for a sample size of = 100 by using = 0.05. You also want to plot power for sample sizes between 50 and 150. Use the MULTREG statement to compute the power and the PLOT statement to produce the graph. Since the predictors are observed rather than fixed in advanced, and a joint multivariate normal assumption seems tenable, use MODEL=RANDOM. The following statements perform the power analysis:

```proc power;
multreg
model = random
nfullpredictors = 7
ntestpredictors = 1
partialcorr = 0.35
ntotal = 100
power = .;
plot x=n min=50 max=150;
run;
```

The POWER=. option identifies power as the parameter to compute. The NFULLPREDICTORS= option specifies seven total predictors (not including the intercept), and the NTESTPREDICTORS= option indicates that one of those predictors is being tested. The PARTIALCORR= and NTOTAL= options specify the partial correlation and sample size, respectively. The default value for the ALPHA= option sets the significance level to 0.05. The X=N option in the plot statement requests a plot of sample size on the X axis, and the MIN= and MAX= options specify the sample size range.

Output 68.5.1 shows the output, and Output 68.5.2 shows the plot.

Output 68.5.1 Power Analysis for Multiple Regression
The POWER Procedure
Type III F Test in Multiple Regression

Fixed Scenario Elements
Method Exact
Model Random X
Number of Predictors in Full Model 7
Number of Test Predictors 1
Partial Correlation 0.35
Total Sample Size 100
Alpha 0.05

Computed Power
Power
0.939

Output 68.5.2 Plot of Power versus Sample Size for Multiple Regression For the sample size = 100, the study is almost balanced with respect to Type I and Type II error rates, with = 0.05 and = 1 – 0.937 = 0.063. The study thus seems well designed at this sample size.

Now suppose that in a follow-up meeting with the cardiologists, you discover that their specific intent is to demonstrate that the (partial) correlation between PBI and tHcy is greater than 0.2. You suggest changing the planned data analysis to a one-sided Fisher’s test with a null correlation of 0.2. The following statements perform a power analysis for this test:

```proc power;
onecorr dist=fisherz
npvars = 6
corr = 0.35
nullcorr = 0.2
sides = 1
ntotal = 100
power = .;
run;
```

The DIST=FISHERZ option in the ONECORR statement specifies Fisher’s test. The NPARTIALVARS= option specifies that six additional variables are adjusted for in the partial correlation. The CORR= option specifies the conjectured correlation of 0.35, and the NULLCORR= option indicates the null value of 0.2. The SIDES= option specifies a one-sided test.

Output 68.5.3 shows the output.

Output 68.5.3 Power Analysis for Fisher’s z Test
The POWER Procedure
Fisher's z Test for Pearson Correlation

Fixed Scenario Elements
Distribution Fisher's z transformation of r
Method Normal approximation
Number of Sides 1
Null Correlation 0.2
Number of Variables Partialled Out 6
Correlation 0.35
Total Sample Size 100
Nominal Alpha 0.05

Computed Power
Actual Alpha Power
0.05 0.466

The power for Fisher’s test is less than 50%, the decrease being mostly due to the smaller effect size (relative to the null value). When asked for a recommendation for a new sample size goal, you compute the required sample size to achieve a power of 0.95 (to balance Type I and Type II errors) and 0.85 (a threshold deemed to be minimally acceptable to the team). The following statements perform the sample size determination:

```proc power;
onecorr dist=fisherz
npvars = 6
corr = 0.35
nullcorr = 0.2
sides = 1
ntotal = .
power = 0.85 0.95;
run;
```

The NTOTAL=. option identifies sample size as the parameter to compute, and the POWER= option specifies the target powers.

Output 68.5.4 Sample Size Determination for Fisher’s z Test
The POWER Procedure
Fisher's z Test for Pearson Correlation

Fixed Scenario Elements
Distribution Fisher's z transformation of r
Method Normal approximation
Number of Sides 1
Null Correlation 0.2
Number of Variables Partialled Out 6
Correlation 0.35
Nominal Alpha 0.05

Computed N Total
Index Nominal Power Actual Alpha Actual Power N Total
1 0.85 0.05 0.850 280
2 0.95 0.05 0.950 417

The results in Output 68.5.4 reveal a required sample size of 417 to achieve a power of 0.95 and a required sample size of 280 to achieve a power of 0.85. Previous Page | Next Page | Top of Page