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| The FACTOR Procedure |
This example illustrates how you can utilize the standard errors and confidence intervals to understand the pattern of factor loadings under the maximum likelihood estimation. There are nine tests and you want a three-factor solution for a correlation matrix based on 200 observations. You apply quartimin rotation with (default) Kaiser normalization. You define loadings with magnitudes greater than 0.45 to be salient and use 90% confidence intervals to judge the salience:
data test(type=corr);
title 'Quartimin-Rotated Factor Solution with Standard Errors';
input _name_ $ test1-test9;
_type_ = 'corr';
datalines;
Test1 1 .561 .602 .290 .404 .328 .367 .179 -.268
Test2 .561 1 .743 .414 .526 .442 .523 .289 -.399
Test3 .602 .743 1 .286 .343 .361 .679 .456 -.532
Test4 .290 .414 .286 1 .677 .446 .412 .400 -.491
Test5 .404 .526 .343 .677 1 .584 .408 .299 -.466
Test6 .328 .442 .361 .446 .584 1 .333 .178 -.306
Test7 .367 .523 .679 .412 .408 .333 1 .711 -.760
Test8 .179 .289 .456 .400 .299 .178 .711 1 -.725
Test9 -.268 -.399 -.532 -.491 -.466 -.306 -.760 -.725 1
;
proc factor data=test method=ml reorder rotate=quartimin
nobs=200 n=3 se cover=.45 alpha=.1;
title2 'A nine-variable-three-factor example';
run;
Output 2.1.1: Quartimin-Rotated Factor Solution with Standard Errors
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