Declining Balance (DB)
Recall that the Straight Line method assumes a constant depreciation value.
Conversely, the Declining Balance method assumes a
constant depreciation rate per year.
And like the Sum-of-years method, more depreciation tends to
occur earlier in the asset's life.
Assume the price of a depreciating asset is P and its salvage value
after N years is S.
You could assume the asset depreciates by a factor of
(or a rate o
f
%).
This method is known as Single Declining Balance.
In an equation this looks like:
Annual Depreciation =

Previous year's value
So for our example, the depreciation during the first year is
-
[$20,000/5] = $4,000
Table 11.3 describes how Declining Balance would depreciate the
asset.
Table 11.3: Declining Balance Example
|
Year
|
Depreciation
|
Year-end Value
|
| 1 | [$20,000.00/5] = $4,000.00 | $16,000.00 |
| 2 | [$16,000.00/5] = $3,200.00 | $12,800.00 |
| 3 | [$12,800.00/5] = $2,560.00 | $10,240.00 |
| 4 | [$10,240.00/5] = $2,560.00 | $8,192.00 |
| 5 | [$12,800.00/5] = $2,560.00 | $6,553.60 |
You could also accelerate the depreciation by increasing
the factor (and hence the rate) at which depreciation occurs.
Other commonly accepted depreciation rates are
% (called Double Declining Balance as the depreciation factor
becomes
) and
%.
Investment Analysis enables you to choose between these three
types for Declining Balance: 2 (with
% depreciation),
1.5 (with
%), and 1 (with
%).
Declining Balance and the Salvage Value
The Declining Balance method assumes that depreciation is faster
earlier in an asset's life; this is what you wanted.
But notice the final value is greater than the salvage value.
Even if the salvage value were greater than $6,553.60,
the final year-end value would not change.
The salvage value never enters the calculation,
so there is no way for the salvage value to force the depreciation to assume
its value.
Newnan and Lavelle (1998) describe two ways to adapt the
Declining Balance method to assume the salvage value at the final time.
One way is as follows:
Suppose you call the depreciated value after i years V(i).
This sets V(0)=P and V(N)=S.
- If V(N)>S according to the usual calculation for V(N),
redefine V(N) to equal S.
- If V(i)<S according to the usual calculation for V(i) for some i
(and hence for all subsequent V(i) values), you can redefine all such
V(i) to equal S.
This alteration to Declining Balance forces
the depreciated value of the asset after N years to be S and
keeps V(i) no less than S.
The second (and preferred) way to force Declining Balance to
assume the salvage value is by Conversion to Straight Line.
If V(N)>S, the first way redefines V(N) to equal S; you can think
of this as
converting to the Straight Line method for the last timestep.
If the V(N) value supplied by DB is appreciably larger than S,
then the depreciation in the final year would be unrealistically large.
An alternate way is to compute the DB and SL step at each
timestep and take whichever step gives a larger depreciation (unless
DB drops below the salvage value).
Once SL assumes a larger depreciation,
it continues to be larger over the life of the asset.
This forces the value at the
final time to equal the salvage value as SL forces this.
As an algorithm, this looks like
V(0) = P;
for i=1 to N
if DB step > SL step from (i,V(i))
take a DB step to make V(i);
else
break;
for j = i to N
take a SL step to make V(j);
The MACRS discussed in Depreciation Table...
is actually a variation on the Declining Balance with conversion to
Straight Line method.
Copyright © 2000 by SAS Institute Inc., Cary, NC, USA. All rights reserved.