Practical Problem-Solving with PROC SQL |
Problem |
You want to update values in a column of a table, based on the values of several other columns in the table.
Background Information |
There is one table, called INCENTIVES, that contains information on sales data. There is one record for each salesperson that includes a department code, a base pay rate, and sales of two products, gadgets and whatnots.
Sample Input Data to Conditionally Change a Table
Sales Data for Incentives Program Name Department Payrate Gadgets Whatnots ------------------------------------------------------------ Lao Che M2 8 10193 1105 Jack Colton U2 6 9994 2710 Mickey Raymond M1 12 6103 1930 Dean Proffit M2 11 3000 1999 Antoinette Lily E1 20 2203 4610 Sydney Wade E2 15 4205 3010 Alan Traherne U2 4 5020 3000 Elizabeth Bennett E1 16 17003 3003
You want to update the table by increasing each salesperson's payrate (based on the total sales of gadgets and whatnots) and taking into consideration some factors that are based on department code.
Specifically, anyone who sells over 10,000 gadgets merits an extra $5 per hour. Anyone selling between 5,000 and 10,000 gadgets also merits an incentive pay, but E Department salespersons are expected to be better sellers than those in the other departments, so their gadget sales incentive is $2 per hour compared to $3 per hour for those in other departments. Good sales of whatnots also entitle sellers to added incentive pay. The algorithm for whatnot sales is that the top level (level 1 in each department) salespersons merit an extra $.50 per hour for whatnot sales over 2,000, and level 2 salespersons merit an extra $1 per hour for sales over 2,000.
Solution |
Use the following PROC SQL code to create a new value for the Payrate column. Actually Payrate is updated twice for each row, once based on sales of gadgets, and again based on sales of whatnots:
proc sql; update incentives set payrate = case when gadgets > 10000 then payrate + 5.00 when gadgets > 5000 then case when department in ('E1', 'E2') then payrate + 2.00 else payrate + 3.00 end else payrate end; update incentives set payrate = case when whatnots > 2000 then case when department in ('E2', 'M2', 'U2') then payrate + 1.00 else payrate + 0.50 end else payrate end; title 'Adjusted Payrates Based on Sales of Gadgets and Whatnots'; select * from incentives;
PROC SQL Output for Conditionally Updating a Table
Adjusted Payrates Based on Sales of Gadgets and Whatnots Name Department Payrate Gadgets Whatnots ------------------------------------------------------------ Lao Che M2 13 10193 1105 Jack Colton U2 10 9994 2710 Mickey Raymond M1 15 6103 1930 Dean Proffit M2 11 3000 1999 Antoinette Lily E1 20.5 2203 4610 Sydney Wade E2 16 4205 3010 Alan Traherne U2 8 5020 3000 Elizabeth Bennett E1 21.5 17003 3003
How It Works |
This solution performs consecutive updates to the payrate column of the incentive table. The first update uses a nested case expression, first determining a bracket that is based on the amount of gadget sales: greater than 10,000 calls for an incentive of $5, between 5,000 and 10,000 requires an additional comparison. That is accomplished with a nested case expression that checks department code to choose between a $2 and $3 incentive.
update incentives set payrate = case when gadgets > 10000 then payrate + 5.00 when gadgets > 5000 then case when department in ('E1', 'E2') then payrate + 2.00 else payrate + 3.00 end else payrate end;
The second update is similar, though simpler. All sales of whatnots over 2,000 merit an incentive, either $.50 or $1 depending on the department level, that again is accomplished by means of a nested case expression.
update incentives set payrate = case when whatnots > 2000 then case when department in ('E2', 'M2', 'U2') then payrate + 1.00 else payrate + 0.50 end else payrate end;
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